0.04x^2=10

Solution for 0.04x^2=10 equation:

0.04x^2=10

We move all terms to the left:

0.04x^2-(10)=0

a = 0.04; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·0.04·(-10)
Δ = 1.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.6}}{2*0.04}=\frac{0-\sqrt{1.6}}{0.08}
=-\frac{\sqrt{}}{0.08}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.6}}{2*0.04}=\frac{0+\sqrt{1.6}}{0.08}
=\frac{\sqrt{}}{0.08}
$